document.write( "Question 268621: An air rescue plane averages 300 miles per hour in still air. It carries enough fuel for 5 hours of flying time. If, upon takeoff it encounters a head wind of 30 mi/hr and the wind remains constant, how far can the plane fly and then return safely?\r
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document.write( "Is the rate simply 300-30? How do I find the distance traveled? \n" );
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Algebra.Com's Answer #196911 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! An air rescue plane averages 300 miles per hour in still air. \n" ); document.write( " It carries enough fuel for 5 hours of flying time. \n" ); document.write( " If, upon takeoff it encounters a head wind of 30 mi/hr and the wind remains constant, how far can the plane fly and then return safely? \n" ); document.write( ": \n" ); document.write( "Effective ground speed \n" ); document.write( "300 - 30 = 270 mph against the wind \n" ); document.write( "300 + 30 = 330 mph with the wind \n" ); document.write( ": \n" ); document.write( "Let d = the one-way distance; write a time equation, time = dist/speed \n" ); document.write( ": \n" ); document.write( "outbound time + return time = 5 hrs \n" ); document.write( " \n" ); document.write( "Multiply by 81900 (270*330), eliminate the denominators, results: \n" ); document.write( "330d + 270d = 5(81900) \n" ); document.write( "600d = 445500 \n" ); document.write( "6d = 4455 \n" ); document.write( "d = \n" ); document.write( "d = 742.5 mi, the plane can fly out and return safely \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check this by finding the total time \n" ); document.write( "742.5/270 + 742.5/330 = \n" ); document.write( "2.75 + 2.25 = 5 \n" ); document.write( " \n" ); document.write( " |