document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=268706>Question 268706</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The larger of two numbers is 4 less than 3 times the smaller number.  If 3 more than twice the larger number is decreased by twice the smaller number, the result is 11.  Find the numbers. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #196909 by </B><A HREF=/tutors/aboutme.mpl?userid=dabanfield><B>dabanfield(803)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=dabanfield><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=196909\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The larger of two numbers is 4 less than 3 times the smaller number. If 3 more than twice the larger number is decreased by twice the smaller number, the result is 11. Find the numbers.\r<BR>\n" );
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document.write( "Let x be the smaller number and y the larger number. Then we have:\r<BR>\n" );
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document.write( "1.) y = 3x - 4<BR>\n" );
document.write( "2.) (2y + 3) - 2x = 11\r<BR>\n" );
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document.write( "Substitute 3x-4 for y from equation 1.) in equation 2.) and solve for x. Then calculate y = 3x-4  </SPAN>\n" );
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