document.write( "Question 268701: A car A left city X traveling 60 mph.2 hours later a car B leaves City X, traveling the same road at 70 mph. When will car B reach car A? How far will each car have traveled?\r
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document.write( "I really need help putting this into an equation then I will be able to solve it myself. \r
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document.write( "Thanks! \n" );
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Algebra.Com's Answer #196893 by drk(1908)![]() ![]() ![]() You can put this solution on YOUR website! This is an RTD problem. Here is a table based on the given information \n" ); document.write( "cars . . . . . . . . . rate . . . . . . . . .time . . . . . . . . distance \n" ); document.write( "A. . . . . . . . . . . .60. . . . . . . . . . x . . . . . . . . . . . .60x \n" ); document.write( "B. . . . . . . . . . . . 70 . . . . . . . . . .x -2 . . . . . . . . . 70x - 140 \n" ); document.write( "since the distances are equal, we get \n" ); document.write( "60x = 70x - 140 \n" ); document.write( "subtract 70x to get \n" ); document.write( "-10x = -140 \n" ); document.write( "x = 14 \n" ); document.write( "It will take 14 hours for B to reach A \n" ); document.write( "60*14 = 840 miles \n" ); document.write( " |