document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=268688>Question 268688</A>: <I><SPAN STYLE=\"word-break: break-all;\"> -4j^2+3j-28=0 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #196884 by </B><A HREF=/tutors/aboutme.mpl?userid=persian52><B>persian52(161)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=persian52><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=persian52><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=196884\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You want to solve using the quadratic formula? IF yes then here!\r<BR>\n" );
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document.write( "-4j^(2)+3j-28=0\r<BR>\n" );
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document.write( "Since -28 does not contain the variable to solve for, move it to the right-hand side of the equation by adding 28 to both sides.<BR>\n" );
document.write( "-4j^(2)+3j=28\r<BR>\n" );
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document.write( "To set the left-hand side of the equation equal to 0, move all the expressions to the left-hand side.<BR>\n" );
document.write( "-4j^(2)+3j-28=0\r<BR>\n" );
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document.write( "Multiply each term in the equation by -1.<BR>\n" );
document.write( "-4j^(2)*-1+3j*-1-28*-1=0*-1\r<BR>\n" );
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document.write( "Simplify the left-hand side of the equation by multiplying out all the terms.<BR>\n" );
document.write( "4j^(2)-3j+28=0*-1\r<BR>\n" );
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document.write( "Multiply 0 by -1 to get 0.<BR>\n" );
document.write( "4j^(2)-3j+28=0\r<BR>\n" );
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document.write( "Use the quadratic formula to find the solutions.  In this case, the values are a=4, b=-3, and c=28.<BR>\n" );
document.write( "j=(-b\~(b^(2)-4ac))/(2a) where aj^(2)+bj+c=0\r<BR>\n" );
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document.write( "Substitute in the values of a=4, b=-3, and c=28.<BR>\n" );
document.write( "j=(-(-3)\~((-3)^(2)-4(4)(28)))/(2(4))\r<BR>\n" );
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document.write( "Multiply -1 by the -3 inside the parentheses.<BR>\n" );
document.write( "j=(3\~((-3)^(2)-4(4)(28)))/(2(4))\r<BR>\n" );
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document.write( "Simplify the section inside the radical.<BR>\n" );
document.write( "j=(3\i~(439))/(2(4))\r<BR>\n" );
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document.write( "Simplify the denominator of the quadratic formula.<BR>\n" );
document.write( "j=(3\i~(439))/(8)\r<BR>\n" );
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document.write( "First, solve the + portion of ±.<BR>\n" );
document.write( "j=(3+i~(439))/(8)\r<BR>\n" );
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document.write( "Next, solve the - portion of ±.<BR>\n" );
document.write( "j=(3-i~(439))/(8)\r<BR>\n" );
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document.write( "The final answer is the combination of both solutions.<BR>\n" );
document.write( "j=(3+i~(439))/(8),(3-i~(439))/(8) </SPAN>\n" );
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