document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=268680>Question 268680</A>: <I><SPAN STYLE=\"word-break: break-all;\"> One leg of a right triangle is 6 cm shorter than the other leg. The length of the hypotenuse is 30 cm. Find the length of the longer leg. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #196873 by </B><A HREF=/tutors/aboutme.mpl?userid=palanisamy><B>palanisamy(496)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=palanisamy><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=196873\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the length of the longer leg = x<BR>\n" );
document.write( "Then, x^2+(x-6)^2=30^2<BR>\n" );
document.write( "      x^2+x^2-12x+36-900=0<BR>\n" );
document.write( "2x^2-12x-864=0<BR>\n" );
document.write( "x^2-6x-432=0<BR>\n" );
document.write( "(x+18)(x-24) =0<BR>\n" );
document.write( "x = -18 or x=24<BR>\n" );
document.write( "x cannot be negative<BR>\n" );
document.write( "so x=24 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );