document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=268670>Question 268670</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If a 26 ft long ladder rest against a wall.  the distance from the base of the wall to the bottom of the ladder is x. The height at which the ladder rests against the wall is x+14. find the distance, x, from the base of the wall to the bottom of the ladder. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #196870 by </B><A HREF=/tutors/aboutme.mpl?userid=palanisamy><B>palanisamy(496)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=palanisamy><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=196870\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The ladder forms a right triangle with the wall'<BR>\n" );
document.write( "So, x^2+(x+14)^2 = 26^2<BR>\n" );
document.write( "    x^2+x^2+28x+196 = 676<BR>\n" );
document.write( "    2x^2+28x-480=0<BR>\n" );
document.write( "x^2+14x-240=0<BR>\n" );
document.write( "(x+24)(x-10)=0<BR>\n" );
document.write( "x=-24 or x=10<BR>\n" );
document.write( "x cannot be negative<BR>\n" );
document.write( "So, x=10<BR>\n" );
document.write( "  </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );