document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=268619>Question 268619</A>: <I><SPAN STYLE=\"word-break: break-all;\"> find a number such that three times the number increased b 7 is 52 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #196831 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=196831\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">     find a number such that three times the number increased by 7 is 52<BR>\n" );
document.write( ".<BR>\n" );
document.write( "Let x = the number<BR>\n" );
document.write( "then<BR>\n" );
document.write( "3x + 7 = 52<BR>\n" );
document.write( "3x = 52-7<BR>\n" );
document.write( "3x = 45<BR>\n" );
document.write( "x = 15 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );