document.write( "Question 268591: the trip is 80 miles long, 40 miles out and 40 miles back. If the bus travels at a speed of 50 mph on the way out and 30 mph on the wat back. How many minutes will the class be on the bus?\r
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Algebra.Com's Answer #196830 by nerdybill(7384)\"\" \"About 
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the trip is 80 miles long, 40 miles out and 40 miles back. If the bus travels at a speed of 50 mph on the way out and 30 mph on the wat back. How many minutes will the class be on the bus?
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\n" ); document.write( "Apply the distance formula:
\n" ); document.write( "d = rt
\n" ); document.write( "but in your case you're interested in time so solving for t:
\n" ); document.write( "t = d/r
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\n" ); document.write( "Time going out:
\n" ); document.write( "t = d/r
\n" ); document.write( "t = 40/50 = 4/5 hour
\n" ); document.write( "Time coming back:
\n" ); document.write( "t = d/r
\n" ); document.write( "t = 40/30 = 4/3 hour
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\n" ); document.write( "Total = 4/5 + 4/3
\n" ); document.write( "Total = 12/15 + 20/15
\n" ); document.write( "Total = 22/15 hour
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\n" ); document.write( "Convert \"total time\" to minutes:
\n" ); document.write( "22/15 * 60 = 88 minutes
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