document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=268603>Question 268603</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of three numbers is 69. If the second number is equal to the first diminished by 8, and the third number is 5 times the first. What are the numbers? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #196821 by </B><A HREF=/tutors/aboutme.mpl?userid=drk><B>drk(1908)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=drk><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=196821\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a + b + c = 69<BR>\n" );
document.write( "b = a - 8<BR>\n" );
document.write( "c = 5a<BR>\n" );
document.write( "---<BR>\n" );
document.write( "by substitution, we get<BR>\n" );
document.write( "a + a - 8 + 5a = 69<BR>\n" );
document.write( "combine like terms to get<BR>\n" );
document.write( "7a - 8 = 69<BR>\n" );
document.write( "add 8 to get<BR>\n" );
document.write( " 7a = 77<BR>\n" );
document.write( "divide to get<BR>\n" );
document.write( " a = 11<BR>\n" );
document.write( "b = 3<BR>\n" );
document.write( "c = 55 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );