document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=268556>Question 268556</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a rectangle with a perimeter of 40 centimeters is 5 centimeters longer than twice its width. find the length of each side, then find the area<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #196808 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=196808\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> L=2W+5<BR>\n" );
document.write( "2L+2W=40<BR>\n" );
document.write( "2(2W+5)+2W=40<BR>\n" );
document.write( "4W+10+2W=40<BR>\n" );
document.write( "6W=40-10<BR>\n" );
document.write( "6W=30<BR>\n" );
document.write( "W=30/6<BR>\n" );
document.write( "W=5 ANS. FOR THE WIDTH.<BR>\n" );
document.write( "L=2*5+5<BR>\n" );
document.write( "L=10+5=15 ANS. FOR THE LENGTH.<BR>\n" );
document.write( "PROOF:<BR>\n" );
document.write( "2*15+2*5=40<BR>\n" );
document.write( "30+10=40<BR>\n" );
document.write( "40=40<BR>\n" );
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