document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=268575>Question 268575</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two cyclists start biking from a trail's start 3 hours apart. The second cyclist travels at 10 miles per hour and starts 3 hours after the first cyclist who is traveling at 6 miles per hour. How much time will pass before the second cyclist catches up with the first from the time the second cyclist started biking? \r<BR>\n" );
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document.write( "t=d/s<BR>\n" );
document.write( "I know the answer is 4.5 hours but am having problems setting up the equations.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #196805 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=196805\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> d=rt<BR>\n" );
document.write( "d=6t  for the first cyclist.<BR>\n" );
document.write( "d=10(t-3) for the second cyclist.<BR>\n" );
document.write( "Because the distances are the same set the 2 equations equal. <BR>\n" );
document.write( "6t=10(t-3)<BR>\n" );
document.write( "6t=10t-30<BR>\n" );
document.write( "6t-10t=-30<BR>\n" );
document.write( "-4t=-30<BR>\n" );
document.write( "t=30/4<BR>\n" );
document.write( "t=7.5 hours after the first cyclist leaves.<BR>\n" );
document.write( "7.5-3=4.5 hours after the second cyclist leaves. </SPAN>\n" );
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