document.write( "Question 268576: the product of 2 consecutive positive integers in 71 more than their sum. Find the integers.\r
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Algebra.Com's Answer #196803 by checkley77(12844)\"\" \"About 
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Let x & (x+1) be the 2 integers.
\n" ); document.write( "x(x+1)=x+x+1+71
\n" ); document.write( "x^2+x=2x+72
\n" ); document.write( "x^2+x-2x-72=0
\n" ); document.write( "(x^2-x-72=0
\n" ); document.write( "(x-9)(x+8)=0
\n" ); document.write( "x-9=0
\n" ); document.write( "x=9 ans.
\n" ); document.write( "9+1=10 ans.
\n" ); document.write( "9*10=9+10+71
\n" ); document.write( "90=90
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