document.write( "Question 268571: The first and third of three consecutive odd intergers are added, the result is 69 less than five times the second interger. What is the third interger? \n" ); document.write( "
Algebra.Com's Answer #196793 by stanbon(75887)\"\" \"About 
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The first and third of three consecutive odd integers are added, the result is 69 less than five times the second integer. What is the third integer?
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\n" ); document.write( "Note: integer has only one \"r\".
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\n" ); document.write( "1st: 2x-1
\n" ); document.write( "2nd: 2x+1
\n" ); document.write( "3rd: 2x+3
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\n" ); document.write( "Equation:
\n" ); document.write( "(2x-1) + (2x+3) = 5(2x+1)-69
\n" ); document.write( "4x+2 = 10x-64
\n" ); document.write( "6x = 66
\n" ); document.write( "x = 11
\n" ); document.write( "----
\n" ); document.write( "1st: 2x-1 = 21
\n" ); document.write( "2nd: 2x+1 = 23
\n" ); document.write( "3rd: 2x+3 = 25
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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