document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=33156>Question 33156</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Norma invested the start-up capital for her Internet business in two hedge funds.  After one year one of the funds returned 5% and the other returned 6% for a total return of $5880. If the amount on which she made 6% was $10,000 larger than the amount on which she made 5%, then what was the original amount of her start-up capital? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #19679 by </B><A HREF=/tutors/aboutme.mpl?userid=mukhopadhyay><B>mukhopadhyay(490)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mukhopadhyay><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=19679\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Investment at 5% = x dollars;<BR>\n" );
document.write( "Investment at 6% = 10000+x;<BR>\n" );
document.write( "Earnings in 1 year from 5% investment = .05x;<BR>\n" );
document.write( "Earnings in 1 year from 6% investment = .06(10000+x);<BR>\n" );
document.write( "Total earnings in 1 year = $5,880<BR>\n" );
document.write( "=> .05x + .06(10000+x) = 5880<BR>\n" );
document.write( "=> .11x + 600 = 5880<BR>\n" );
document.write( "=> x = 5280/.11 = 48000;<BR>\n" );
document.write( "Answer: The original amount of her start-up capital is $48,000+$58,000=$106,000 </SPAN>\n" );
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