document.write( "Question 268391: .A and B can do a piece of work in 12 days,B and C can do it in 15 days and C and A can do
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document.write( " the same work in 20 days. How long would each take to complete the job? \n" );
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Algebra.Com's Answer #196783 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Let the piece of work = 1 \n" ); document.write( ": \n" ); document.write( "Write a shared work equation for each phrase: \n" ); document.write( ": \n" ); document.write( "A and B can do a piece of work in 12 days, \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "B and C can do it in 15 days and \n" ); document.write( " \n" ); document.write( "; \n" ); document.write( " C and A can do the same work in 20 days. \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "Use elimination; Mult the 1st eq by 5, mult the 3nd eq by 3 \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "------------------------------Subtraction eliminates A, leaving us with \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "Multiply the 2nd equation by 4, add to the above equation \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "-------------------------------addition eliminates C, find B \n" ); document.write( " \n" ); document.write( "120 = 6B \n" ); document.write( "B = \n" ); document.write( "B = 20 hrs working alone \n" ); document.write( ": \n" ); document.write( "Use the 2nd equation to find C, substitute 20 for B, find C \n" ); document.write( " \n" ); document.write( "Multiply by 20C, results: \n" ); document.write( "15C + 20(15) = 20C \n" ); document.write( "15C + 300 = 20C \n" ); document.write( "300 = 20C - 15C \n" ); document.write( "5C = 300 \n" ); document.write( "C = \n" ); document.write( "C = 60 hrs working alone \n" ); document.write( ": \n" ); document.write( "Use the 3rd equation to find A \n" ); document.write( " \n" ); document.write( "Multiply by 60A \n" ); document.write( "60(20) + 20A = 60A \n" ); document.write( "1200 = 60A - 20A \n" ); document.write( "40A = 1200 \n" ); document.write( "A = \n" ); document.write( "A = 30 hrs working alone \n" ); document.write( ": \n" ); document.write( "Summarize: A=30; B=20; C=60 \n" ); document.write( "; \n" ); document.write( ": \n" ); document.write( "Check it in the 1st equation \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "YOu can confirm it in the other two equations. \n" ); document.write( " |