document.write( "Question 33208: By using the formula logba = (log a)/(log b) where the b is lowered solve log2 10000 where the two is lowered
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Algebra.Com's Answer #19678 by mukhopadhyay(490) $\"\"$ $\"About$

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log (base2) 10000 = (log 10000)/(log 2) = (log 10^4)/(log 2) = 4/(log 2) \n" ); document.write( "

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