document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=33263>Question 33263</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A fourth-grade class decides to enclose a rectangular garden, using the side of the school as one side of the rectangle.  What is the maximum area that the class can enclose with 32 ft of fence?  What should the dimensions of the garden be in order to yield this area? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #19675 by </B><A HREF=/tutors/aboutme.mpl?userid=venugopalramana><B>venugopalramana(3286)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=venugopalramana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.geocities.com/venugopalramana/FREE_MATHS_ASSISTANCE.html valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=19675\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> TOTAL FENCING=32=L+L+B+B=2(L+B)<BR>\n" );
document.write( "L+B=16.......L=16-B<BR>\n" );
document.write( "AREA=LB=B(16-B)=16B-B^2=-(B^2-16B)=-(B^2-2B*8+8^2-8^2)=64-(B-8)^2<BR>\n" );
document.write( "(B-8)^2BENIG A PERFRC SQUARE IS ALWAYS POSITIVE.SINCE IT IS HAVING A MINUS SIGN INFRONT AREA WILL BE MAXIMUM WHEN THIS IS ZERO..THAT IS B-8=0..OR...B=8<BR>\n" );
document.write( "SO L=8 AND B=8 IS THE SOLUTION WHICH GIVES MAXIMUM AREA OF 64 </SPAN>\n" );
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