document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=268473>Question 268473</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A student invests part of $10,000 at 6% annual interest and the rest at 5%.  If the annual income from these investments is $560, how much was invested at each rate? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #196743 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=196743\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> .06x+.05(10,000-x)=560<BR>\n" );
document.write( ".06x+500-.05x=560<BR>\n" );
document.write( ".01x=560-500<BR>\n" );
document.write( ".01x=60<BR>\n" );
document.write( "x=60/.01<BR>\n" );
document.write( "x=6,000 amount invested @ 6%<BR>\n" );
document.write( "10,000-6,000=4,000 amount invested @ 5%<BR>\n" );
document.write( "Proof:<BR>\n" );
document.write( ".06*6,000+.05*4,000=560<BR>\n" );
document.write( "360+200=560<BR>\n" );
document.write( "560=560<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );