document.write( "Question 268140: A person invested a sum of money at 9% annual simple interest and invested twice that amount at 11% annual simple interest. If the total yearly income from both investments was $1,395 how much was invested at each rate?\r
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Algebra.Com's Answer #196731 by ankor@dixie-net.com(22740) You can put this solution on YOUR website! A person invested a sum of money at 9% annual simple interest and invested twice that amount at 11% annual simple interest. \n" ); document.write( " If the total yearly income from both investments was $1,395 how much was invested at each rate? \n" ); document.write( ": \n" ); document.write( "Let x = amt invested at 9% \n" ); document.write( "then \n" ); document.write( "2x = amt invested at 11% \n" ); document.write( ": \n" ); document.write( "a total interest equation \n" ); document.write( ".09x + .11(2x) = 1395 \n" ); document.write( ": \n" ); document.write( ".09x + .22x = 1395 \n" ); document.write( ": \n" ); document.write( ".31x = 1395 \n" ); document.write( "x = \n" ); document.write( "x = $4500 invested at 9% \n" ); document.write( "and, obviously: \n" ); document.write( "2(4500) = $9000 invested at 11% \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check this by finding the total interest with these values: \n" ); document.write( ".09(4500) + .11(9000) = \n" ); document.write( "405 + 990 = 1395 \n" ); document.write( " |