document.write( "Question 268458: 7% interest and 4 times as much at 11%. find the total annual income from if the interest is 7650? \n" ); document.write( "
Algebra.Com's Answer #196729 by checkley77(12844)\"\" \"About 
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.07X+.11*4X=7,650
\n" ); document.write( ".07X+.44X=7,680
\n" ); document.write( ".51X=7,650
\n" ); document.write( "X=7,650/.51
\n" ); document.write( "X=15,000 AMOUNT INVESTED @ 7%.
\n" ); document.write( "4815,000=60,000 AMOUNT INVESTED @ 11%.
\n" ); document.write( "PROOF:
\n" ); document.write( ".07*15,000+.11*60,000=7,650
\n" ); document.write( "1,050+6,600=7,650
\n" ); document.write( "7,650=7,650
\n" ); document.write( "
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