document.write( "Question 268447: The sum of 3 times a number and 4 times another number is 43. Five times the first number is 3 less than four times the opposite of the second number. Find the numbers. \n" ); document.write( "

Algebra.Com's Answer #196726 by drk(1908) $\"\"$ $\"About$

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The sum of 3 times a number and 4 times another number is 43
\n" ); document.write( "translates to
\n" ); document.write( "(i) $\"3x+%2B+4y+=+43\"$
\n" ); document.write( "Five times the first number is 3 less than four times the opposite of the second number
\n" ); document.write( "translates to
\n" ); document.write( "(ii) $\"5x+=+4%28-y%29+-+3\"$
\n" ); document.write( "step 1 - rewrite (ii) so that x and y are on the same side to get
\n" ); document.write( "(iii) $\"5x+%2B+4y+=+-3\"$
\n" ); document.write( "step 2 - multiply (iii) by -1 to get
\n" ); document.write( "(iv) $\"-5x+-+4y+=+3\"$
\n" ); document.write( "step 3 - add (i) and (iv) to get
\n" ); document.write( "(v) $\"-2x+=+46\"$
\n" ); document.write( "step 4 - divide to get
\n" ); document.write( "(vi) $\"+x+=+-23\"$
\n" ); document.write( "Step 5 - solve for y to get
\n" ); document.write( " $\"y+=+28\"$ \n" ); document.write( "

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