document.write( "Question 33270: the length of a rectangle exceeds it's width by 8 inches, and the area is 20 square inches. what is the length of the rectangle? \n" ); document.write( "
Algebra.Com's Answer #19672 by sarah_adam(201)\"\" \"About 
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Let the length and width of rectangle be L and W
\n" ); document.write( "given:
\n" ); document.write( "L = W+8
\n" ); document.write( "Area = 20 sq inches
\n" ); document.write( "But area = L*W
\n" ); document.write( "20 = L*W
\n" ); document.write( "20 =(8+W)*W
\n" ); document.write( "20 = 8W+\"W%5E2\"
\n" ); document.write( "\"W%5E2\"+8W -20 = 0
\n" ); document.write( "\"W%5E2\"+10W - 2W -20 = 0
\n" ); document.write( "W(W+10)-2(W+10) = 0
\n" ); document.write( "(W-2)(W+10) = 0
\n" ); document.write( "W - 2 = 0 or W +10 = 0
\n" ); document.write( "W = 2 or W = -10 which cannot be as it is a negative value
\n" ); document.write( "so W = 2In
\n" ); document.write( "L = 2+8 = 10 in
\n" ); document.write( "SO length of rectangle is 10 in\r
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