document.write( "Question 268138: I would to know if I could have some help here on this problem. \r
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document.write( "A druggist mixes a 10% soulution of iodine with a 15% solution of iodine. How much of each solution should be used in order to obtain 20 cubic centimeters of a 12% solution?\r
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document.write( "Thank you for your help \n" );
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Algebra.Com's Answer #196710 by ankor@dixie-net.com(22740) You can put this solution on YOUR website! A druggist mixes a 10% solution of iodine with a 15% solution of iodine. \n" ); document.write( " How much of each solution should be used in order to obtain 20 cubic centimeters of a 12% solution? \n" ); document.write( ": \n" ); document.write( "Let x = amt of 15% solution \n" ); document.write( "then \n" ); document.write( "(20-x) = amt of 10% solution \n" ); document.write( ": \n" ); document.write( "A typical mixture equation \n" ); document.write( ".15x + .10(20-x) = .12(20) \n" ); document.write( ".15x + 2 - .10x = 2.4 \n" ); document.write( ".15x - .10x = 2.4 - 2 \n" ); document.write( ".05x = .4 \n" ); document.write( "x = \n" ); document.write( "x = 8 cc of 15% solution required \n" ); document.write( "then \n" ); document.write( "20 - 8 = 12 cc of 10% solution \n" ); document.write( "; \n" ); document.write( ": \n" ); document.write( "Check answer in original mixture equation \n" ); document.write( ".15(8) + .10(12) = .12(20) \n" ); document.write( "1.2 + 1.2 = 2.4 \n" ); document.write( " |