document.write( "Question 268286: Please help with this problem, this is what I have so far:\r
\n" ); document.write( "\n" ); document.write( "Problem: Height of a projected ball,
\n" ); document.write( "An astronaut on the moon throws a baseball upward. The astronaut is 6ft., 6in. tall, and the initial velocity of the ball is 30 ft. per sec. The height S of the ball in feet is given by the equation
\n" ); document.write( "S= -2.7t^2 + 30t + 6.5
\n" ); document.write( "where t is the number of seconds after the ball was thrown.\r
\n" ); document.write( "\n" ); document.write( "A.) After how many seconds is the ball 12ft above the moon's surface? Round to the nearest hundreth.\r
\n" ); document.write( "\n" ); document.write( "I know I have to look for the seconds, which is t so then I have to solve for S, the height. This is have I've got so far:
\n" ); document.write( " 12 = 2.7t^2 + 30t + 6.5
\n" ); document.write( "-12 -12
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\n" ); document.write( " 0 = 2.7t^2 + 30t - 5.5
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\n" ); document.write( "B.)How many seconds will it take fore the ball to return to the surface? Round to the nearest hundredth.\r
\n" ); document.write( "\n" ); document.write( "So on the second part of the equation I have to look for the time, so that means that I have to solve for the height...
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\n" ); document.write( "Thanks for your help in advance.
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Algebra.Com's Answer #196655 by scott8148(6628)\"\" \"About 
You can put this solution on YOUR website!
A.) just use the quadratic formula on the equation you generated and solve for t
\n" ); document.write( "___ watch the signs (your equation has an incorrect sign for the coefficient of the squared term)\r
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\n" ); document.write( "\n" ); document.write( "B.) substitute zero for S in the original equation (S= -2.7t^2 + 30t + 6.5) and use the quadratic formula\r
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\n" ); document.write( "\n" ); document.write( "check the solutions for t to see if they make sense
\n" ); document.write( "___ A should have two solutions (upward and downward)
\n" ); document.write( "___ B should have one solution (negative value not realistic)
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