document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=268189>Question 268189</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A car will go 3/8 of a given distance in one hour.  What part will it cover in 5/8 of an hour? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #196625 by </B><A HREF=/tutors/aboutme.mpl?userid=dabanfield><B>dabanfield(803)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=dabanfield><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=196625\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A car will go 3/8 of a given distance in one hour. What part will it cover in 5/8 of an hour?\r<BR>\n" );
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document.write( "Let D be the GIVEN distance and R the rate. Then since rate = distance/time we have:\r<BR>\n" );
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document.write( "R = (3/8*D)/1<BR>\n" );
document.write( "R = 3/8*D\r<BR>\n" );
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document.write( "Since distance = rate*time the distance d traveled in 5/8 hour is:\r<BR>\n" );
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document.write( "d = (3/8*D)*5/8<BR>\n" );
document.write( "d = 15/64*D\r<BR>\n" );
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document.write( "So the part of the distance traveled is 15/64.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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