document.write( "Question 268178: simplify
\n" ); document.write( "log base 7 75
\n" ); document.write( "choose from these answers
\n" ); document.write( "1.75
\n" ); document.write( "2. 1
\n" ); document.write( "3.5
\n" ); document.write( "4. 5 log base 7 7 \n" ); document.write( "

Algebra.Com's Answer #196617 by jsmallt9(3758) $\"\"$ $\"About$

You can put this solution on YOUR website!
I can only guess the actual expression is:
\n" ); document.write( " $\"log%287%2C+%287%5E5%29%29\"$
\n" ); document.write( "because
\n" ); document.write( " $\"log%287%2C+%2875%29%29\"$ is NOT equal to any of the answers provided.

\n" ); document.write( "If you understand what logarithms are, then this problem is fairly simple. Logarithms are exponents. $\"log%28a%2C+%28b%29%29\"$ represents the exponent which, if placed on a base of a, results in b. Your expression, $\"log%287%2C+%287%5E5%29%29\"$ represents the exponent on 7 that results in $\"7%5E5\"$ . Well, it's pretty obvious that the exponent on 7 that results in $\"7%5E5\"$ is 5! \n" ); document.write( "

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