document.write( "Question 268141: Two buses leave the same city at the same time moving in opposite directions. One travels at a rate of 5 miles per hour faster than the other. After 3 hours they are 375 miles apart. How far did each bus travel?\r
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Algebra.Com's Answer #196586 by josmiceli(19441) $\"\"$ $\"About$

You can put this solution on YOUR website!
speed of slower bus = $\"s\"$
\n" ); document.write( "speed of faster bus = $\"s+%2B+5\"$
\n" ); document.write( "They are moving apart at their combined speeds, which are:
\n" ); document.write( " $\"s+%2B+s+%2B+5\"$
\n" ); document.write( "Let $\"d%5B1%5D\"$ = distance slower bus has gone in mi
\n" ); document.write( "Let $\"d%5B2%5D\"$ = distance faster bus has gone in mi
\n" ); document.write( " $\"d%5B1%5D+%2B+d%5B2%5D+=+375\"$ mi
\n" ); document.write( "Since $\"d+=+r%2At\"$
\n" ); document.write( " $\"375+=+%28s+%2B+s+%2B+5%29%2A3\"$
\n" ); document.write( " $\"375+=+6s+%2B+15\"$
\n" ); document.write( " $\"6s+=+360\"$
\n" ); document.write( " $\"s+=+60\"$
\n" ); document.write( " $\"s+%2B+5+=+65\"$
\n" ); document.write( " $\"d%5B1%5D+=+60%2A3\"$
\n" ); document.write( " $\"d%5B1%5D+=+180\"$ mi
\n" ); document.write( " $\"d%5B2%5D+=+65%2A3\"$
\n" ); document.write( " $\"d%5B2%5D+=+195\"$ mi
\n" ); document.write( "The slower bus went 180 mi, the faster went 195 mi
\n" ); document.write( "check answer:
\n" ); document.write( " $\"375+=+6s+%2B+15\"$
\n" ); document.write( " $\"375+=+6%2A60+%2B+15\"$
\n" ); document.write( " $\"375+=+360+%2B+15\"$
\n" ); document.write( " $\"375+=+375\"$
\n" ); document.write( "OK
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