document.write( "Question 267905: I am having difficulty on the steps to solve this equation:\r
\n" ); document.write( "\n" ); document.write( "e^-x = (e^4)^x+3\r
\n" ); document.write( "\n" ); document.write( "Any help would be greatly appreciated!
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Algebra.Com's Answer #196569 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
Assume the problem is:
\n" ); document.write( "\"e%5E%28-x%29\"=\"%28e%5E4%29%5E%28x%2B3%29\"
\n" ); document.write( ":
\n" ); document.write( "Use the nat logs
\n" ); document.write( "\"ln%28e%5E%28-x%29%29\"=\"ln%28%28e%5E4%29%5E%28x%2B3%29%29\"
\n" ); document.write( ":
\n" ); document.write( "use the log equiv of exponents
\n" ); document.write( "\"-x%2Aln%28e%29\" = \"%28x%2B3%29%2Aln%28e%5E4%29\"
\n" ); document.write( ":
\n" ); document.write( "we know the ln of e = 1, and ln(e^4) = 4, therefore it is greatly simplified
\n" ); document.write( "\"-x%2A1\" = \"%28x%2B3%29%2A%284%29\"
\n" ); document.write( "-x = 4(x+3)
\n" ); document.write( "-x = 4x + 12
\n" ); document.write( "-12 = 4x + x
\n" ); document.write( "-12 = 5x
\n" ); document.write( "x = \"-12%2F5\"
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Check this on your calc
\n" ); document.write( "enter e^(-(-12/5)) = 11.023
\n" ); document.write( "enter (e^4)^((-12/5)+3)= 11.023, equality reigns\r
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