document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=268063>Question 268063</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of the measures of the legs of a right triangle is 48.  The tangent of one of the acute angles is 1/5. What is the measure of the longer leg? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #196564 by </B><A HREF=/tutors/aboutme.mpl?userid=CharlesG2><B>CharlesG2(834)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=CharlesG2><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=196564\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The sum of the measures of the legs of a right triangle is 48. The tangent of one of the acute angles is 1/5. What is the measure of the longer leg?\r<BR>\n" );
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document.write( "tangent is opposite/adjacent is 1/5\r<BR>\n" );
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document.write( "1/5 = x/(48-x)<BR>\n" );
document.write( "1 = 5x/(48-x)<BR>\n" );
document.write( "48-x = 5x<BR>\n" );
document.write( "48 = 6x<BR>\n" );
document.write( "8 = x<BR>\n" );
document.write( "48 - 8 = 40 which is the measure of the longer leg<BR>\n" );
document.write( "8/40 = 1/5 = opposite/adjacent = tangent of one of the acute angles<BR>\n" );
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