document.write( "Question 33265: the width of a rectangle is 5 inches less than its length, and the area is 150 square inches. what is the width of the rectangle? \n" ); document.write( "

Algebra.Com's Answer #19656 by sarah_adam(201) $\"\"$ $\"About$

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let the length and width of the rectangle be L and w
\n" ); document.write( "given:
\n" ); document.write( "w = L-5
\n" ); document.write( "Area = 150 sq inches
\n" ); document.write( "area of the rectangle = L*w
\n" ); document.write( "150 = L*(L-5)
\n" ); document.write( "150 = $\"L%5E2\"$ -5l
\n" ); document.write( " $\"L%5E2\"$ -5L - 150 = 0
\n" ); document.write( " $\"L%5E2\"$ - 15L+10L -150 = 0
\n" ); document.write( "L(L-15)+10(L-15)= 0
\n" ); document.write( "(L+10)(L-15)=0
\n" ); document.write( "(L+10 )= 0 or (L-15) = 0
\n" ); document.write( "L = -10 is not possible as there wont be negative lengths
\n" ); document.write( "so L = 15
\n" ); document.write( "therfore w = L - 5 = 15 - 5 = 10
\n" ); document.write( "L = 15 in and w = 10 in
\n" ); document.write( " \n" ); document.write( "

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