document.write( "Question 268025: A radiator contains 10 quarts of fluid, 25% of which is antifreeze. How much fluid should be drained and replaced with pure antifreeze so that the new mixture is 55% antifreeze? (Round your answer to two decimal places.)
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Algebra.Com's Answer #196520 by josmiceli(19441) $\"\"$ $\"About$

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In words:
\n" ); document.write( "(antifreeze started out with - antifreeze removed + antifreeze added)/(total amout of fluid finally in radiator) = 55%
\n" ); document.write( "Let $\"x\"$ = amount of fluid to be drained
\n" ); document.write( "given:
\n" ); document.write( "Radiator started with:
\n" ); document.write( " $\"10\"$ quarts of fluid
\n" ); document.write( " $\"10%2A.25+=+2.5\"$ quarts antifreeze
\n" ); document.write( " $\".25x\"$ = quarts antifreeze drained
\n" ); document.write( " $\"x\"$ = quarts of pure antifreeze added
\n" ); document.write( "-----------------------------------------
\n" ); document.write( " $\"%282.5+-+.25x+%2B+x%29%2F10+=+.55\"$
\n" ); document.write( "(Note that radiator stated with $\"10\"$ quarts and ended with $\"10\"$ quarts)
\n" ); document.write( " $\"%281.25x+%2B+2.5%29%2F10+=+.55\"$
\n" ); document.write( " $\"1.25x+%2B+2.5+=+5.5\"$
\n" ); document.write( " $\"1.25x+=+3\"$
\n" ); document.write( " $\"x+=+2.4\"$
\n" ); document.write( "2.4 quarts of fluid must be drained and replaced with pure antifreeze
\n" ); document.write( "check answer:
\n" ); document.write( " $\"%282.5+-+.25x+%2B+x%29%2F10+=+.55\"$
\n" ); document.write( " $\"%282.5+-+.25%2A2.4+%2B+2.4%29%2F10+=+.55\"$
\n" ); document.write( " $\"%282.5+-+.6+%2B+2.4%29%2F10+=+.55\"$
\n" ); document.write( " $\"5.5%2F10+=+.55\"$
\n" ); document.write( " $\"5.5+=+5.5\"$
\n" ); document.write( "OK\r
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