document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=267796>Question 267796</A>: <I><SPAN STYLE=\"word-break: break-all;\"> According to a contract, a factory should make 48 tables each day.  Instead, they made 2 additional tables each day until the last 3 days of the contract.  For the last 3 days they only had to make a total of 100 tables.  How many tables was the factory contracted to make? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #196427 by </B><A HREF=/tutors/aboutme.mpl?userid=palanisamy><B>palanisamy(496)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=palanisamy><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=196427\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the total number of tables to be made = x<BR>\n" );
document.write( "According to a contract, a factory should make 48 tables each day.<BR>\n" );
document.write( "The number of days = x/48  ..(1)<BR>\n" );
document.write( "But the factory made 50 tables for [(x/48)-3] days and made 100 tables in the last three days.<BR>\n" );
document.write( "Total number of tables is [(x/48)-3]*50+100 = x<BR>\n" );
document.write( "                          [(x-144)/48]*50 = x-100<BR>\n" );
document.write( "                          [x-144]*50 = 48(x-100)<BR>\n" );
document.write( "                          50x-7200 = 48x-4800<BR>\n" );
document.write( "                          50x-48x = 7200-4800<BR>\n" );
document.write( "                          2x = 2400<BR>\n" );
document.write( "                          x = 2400/2<BR>\n" );
document.write( "                          x = 1200          </SPAN>\n" );
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