document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=33249>Question 33249</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The following is my problem:<BR>\n" );
document.write( "A man has two more nickels than dimes. He has $1.15 in all. How many coins of each kind does he have. I know this looks simple but I cannot figure it out. I keep getting a negative number. Please help! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #19640 by </B><A HREF=/tutors/aboutme.mpl?userid=sarah_adam><B>sarah_adam(201)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=sarah_adam><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=19640\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let number of Nickels be N<BR>\n" );
document.write( "and Number of dimes be D<BR>\n" );
document.write( "given 0.05(D)+ 0.10(N) = 1.15<BR>\n" );
document.write( "ALso given N = 2+D<BR>\n" );
document.write( "so (5/100)D +(10/100)N = 1.15<BR>\n" );
document.write( "5D + 10N = 115<BR>\n" );
document.write( "substitute the value of N <BR>\n" );
document.write( "5D + 10(2+D) = 115<BR>\n" );
document.write( "5D + 20 +10D = 115<BR>\n" );
document.write( "15D = 105<BR>\n" );
document.write( "D = 7<BR>\n" );
document.write( "N = 7+2 = 9<BR>\n" );
document.write( "THerfore Number of Dimes = 7<BR>\n" );
document.write( "Number of Nickels = 2 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );