document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=267743>Question 267743</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the largest angle in a triangle is 50 degrees more than the smallest angle. the sum of the measures of the smaller 2 angles is 10 degrees more than the largest angle. find the measure of each angle </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #196399 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=196399\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the largest angle in a triangle is 50 degrees more than the smallest angle. the sum of the measures of the smaller 2 angles is 10 degrees more than the largest angle. find the measure of each angle<BR>\n" );
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document.write( "Let the smallest angle = x<BR>\n" );
document.write( "Then largest = x+50<BR>\n" );
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document.write( "x + 2nd = x+50+10<BR>\n" );
document.write( "So 2nd = 60<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "x + 60 + x+50 = 180<BR>\n" );
document.write( "2x + 110 = 180<BR>\n" );
document.write( "2x = 70<BR>\n" );
document.write( "x = 35 (smallest)<BR>\n" );
document.write( "2nd = 60 degrees<BR>\n" );
document.write( "x+50 = 85 degrees<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );