document.write( "Question 267425: i dont understand how to do this:\r
\n" ); document.write( "\n" ); document.write( "3x+2y=-6
\n" ); document.write( "x=y+3 \n" ); document.write( "
Algebra.Com's Answer #196396 by ankor@dixie-net.com(22740)\"\" \"About 
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i don't understand how to do this:
\n" ); document.write( "3x + 2y =-6
\n" ); document.write( "x = y+3
\n" ); document.write( ":
\n" ); document.write( "Since x = (y+3), why not substitute (y+3) for x in the 1st equation so you have:
\n" ); document.write( "3(y+3) + 2y = -6
\n" ); document.write( ":
\n" ); document.write( "Multiply what's inside the brackets by 3
\n" ); document.write( "3y + 9 + 2y = -6
\n" ); document.write( ";
\n" ); document.write( "Subtract 9 from both sides, add the y's
\n" ); document.write( "3y + 2y = -6 - 9
\n" ); document.write( "5y = -15
\n" ); document.write( ":
\n" ); document.write( "Divide both sides by 5
\n" ); document.write( "y = \"%28-15%29%2F5\"
\n" ); document.write( "y = -3
\n" ); document.write( ":
\n" ); document.write( "Remember that x = y + 3; substitute -3 for y
\n" ); document.write( "x = (-3) + 3
\n" ); document.write( "x = 0
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Check the solution by substituting for x and y in the 1st equation
\n" ); document.write( "3x + 2y =-6
\n" ); document.write( "3(0) + 2(-3) = -6
\n" ); document.write( "-6 = -6; confirms the solutions \n" ); document.write( "
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