document.write( "Question 267414: You inherit $13,000 and decide to invest the money in two different investments, one paying 10% and the other paying 14%. After 6 months your investments are worth $13,741. How much did you invest in each account? \n" ); document.write( "
Algebra.Com's Answer #196382 by ankor@dixie-net.com(22740)\"\" \"About 
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You inherit $13,000 and decide to invest the money in two different investments, one paying 10% and the other paying 14%.
\n" ); document.write( " After 6 months your investments are worth $13,741.
\n" ); document.write( " How much did you invest in each account?
\n" ); document.write( ":
\n" ); document.write( "We know the interest earned = $741; write a total interest equation
\n" ); document.write( "Let x = amt invested at 14%
\n" ); document.write( "then
\n" ); document.write( "(13000-x) = amt invested at 10%
\n" ); document.write( ":
\n" ); document.write( "We assume the investment return % were per year, but this total is for 6 months
\n" ); document.write( "We have to assume that after 1 yr the amt earned would be 2*741 = $1482
\n" ); document.write( "Using that assumption:
\n" ); document.write( ":
\n" ); document.write( ".14x + .10(13000-x) = 1482
\n" ); document.write( ".14x + 1300 - .10x = 1482
\n" ); document.write( ".14x - .10x = 1482 - 1300
\n" ); document.write( ".04x = 182
\n" ); document.write( "x = \"182%2F.04\"
\n" ); document.write( "x = $4,550 invested at 14%
\n" ); document.write( "and
\n" ); document.write( "13000 - 4550 = $8,450 invested at 10%
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "Check: .14(4550) + .10(8450) =
\n" ); document.write( "637 + 845 = 1482 per year
\n" ); document.write( "then
\n" ); document.write( "781 for half a year\r
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