document.write( "Question 267665: Lucas is 1/3 mile away from home bicycling at 20 miles per hour when his brother takes off on his bike to catch up. How fast must Lucas's brother go to catch him a mile from home. \n" ); document.write( "
Algebra.Com's Answer #196372 by ankor@dixie-net.com(22740)\"\" \"About 
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Lucas is 1/3 mile away from home bicycling at 20 miles per hour when his brother takes off on his bike to catch up.
\n" ); document.write( " How fast must Lucas's brother go to catch him a mile from home.
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\n" ); document.write( "Briefly, bro has to travel 1 mi in the same time that L travels 2/3 of a mile
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\n" ); document.write( "Let s = bro's speed to accomplish difficult feat
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\n" ); document.write( "Write a time equation: Time = dist/speed
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\n" ); document.write( "bro's time = L's time
\n" ); document.write( "\"1%2Fs\" = \"%282%2F3%29%2F20\"
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\n" ); document.write( "\"1%2Fs\" = \"2%2F60\"
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\n" ); document.write( "\"1%2Fs\" = \"1%2F30\"
\n" ); document.write( "Cross multiply
\n" ); document.write( "s = 30 mph bro has pedal to catch L 1 mi from home
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\n" ); document.write( "Check this by finding the times
\n" ); document.write( "1/30 = .033 hrs
\n" ); document.write( ".667/20 = .033 hrs (about 2 min)
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