document.write( "Question 267613: How far can a man drive out into the country at an average rate of 30 mph and return over the same road at an average of 50 mph, if he travels a total time of 8 hours? \n" ); document.write( "
Algebra.Com's Answer #196368 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! D=RT \n" ); document.write( "D=30X DRIVE OUT \n" ); document.write( "D=50(8-X) RETURN TRIP. \n" ); document.write( "DISTANCES ARE EQUAL: \n" ); document.write( "30X=50(8-X) \n" ); document.write( "30X=400-50X \n" ); document.write( "30X+50X=400 \n" ); document.write( "80X=400 \n" ); document.write( "X=400/80 \n" ); document.write( "X=5 HOURS FOR THE DRIVE OUT. \n" ); document.write( "8-5=3 HOURS FOR THE RETURN TRIP. \n" ); document.write( "PROOF: \n" ); document.write( "30*5=50*3 \n" ); document.write( "150=150 MILES IS THE ONE WAY DISTANCE OR \n" ); document.write( "2*150=300 MILES FOR THE ENTIRE RETURN TRIP. \n" ); document.write( " \n" ); document.write( " |