document.write( "Question 267648: f is a linear function.\r
\n" ); document.write( "\n" ); document.write( "If f(5) = -5 and f(-25) = -25, find f(2) and f(50).\r
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\n" ); document.write( "\n" ); document.write( "Thank you so much for helping me! \n" ); document.write( "
Algebra.Com's Answer #196366 by roseo(33)\"\" \"About 
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Think of f(5)=-5 and f(-25) = -25 as points (5,-5) and (-25,-25). Use these 2 points to write the equation of the line that passes through them (because the problem said that this was a linear function). First find the slope
\n" ); document.write( "(-25--5)/(-25-5) = -20/30 which is -2/3. Using the slope intercept form of the line we would have y=-2/3x + b the plug in one of the points to find b. I will use (5,-5)
\n" ); document.write( "-5=-2/3(5)+b
\n" ); document.write( "-5 = -10/3+b
\n" ); document.write( "-5+10/3 = b
\n" ); document.write( "-15/3 +10/3 = b
\n" ); document.write( "-5/3 = b
\n" ); document.write( "Our function is y=-2/3x-5/3
\n" ); document.write( "so f(2) = -2/3(2)-5/3
\n" ); document.write( " -4/3-5/3
\n" ); document.write( " =-9/3
\n" ); document.write( " =-3
\n" ); document.write( "f(50) = -2/3(50)-5/3
\n" ); document.write( " =-100/3-5/3
\n" ); document.write( " =-105/3
\n" ); document.write( " =-35 \n" ); document.write( "
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