document.write( "Question 267524: Need help with the following:\r
\n" ); document.write( "\n" ); document.write( "A box is being constructed by cutting 3-inch squares from the corners of a rectangualr sheet of metal that is 4 inches longer than it is wide. If the box is to have a volume of 135 cubic inches, find the dimensions of the metal sheet.
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Algebra.Com's Answer #196347 by ankor@dixie-net.com(22740)\"\" \"About 
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A box is being constructed by cutting 3-inch squares from the corners of a rectangular sheet of metal that is 4 inches longer than it is wide.
\n" ); document.write( " If the box is to have a volume of 135 cubic inches, find the dimensions of the metal sheet.
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\n" ); document.write( "Assume they mean an open box.
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\n" ); document.write( "Cutting 3\" squares from each corner make the box base dimensions 6\" less than the metal sheet
\n" ); document.write( "We know the height of the box = 3\" therefore:
\n" ); document.write( "Area of the base = \"135%2F3\" = 45 sq/in
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\n" ); document.write( "Let x = width of the metal
\n" ); document.write( "then we can say:
\n" ); document.write( "(x+4) = length of the metal
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\n" ); document.write( "The base of the box dimensions: (x-6) by (x+4-6)
\n" ); document.write( "The area
\n" ); document.write( "(x-6)*(x-2) = 45
\n" ); document.write( "FOIL
\n" ); document.write( "x^2 - 2x - 6x + 12 = 45
\n" ); document.write( "x^2 - 8x + 12 - 45 = 0
\n" ); document.write( "x^2 - 8x - 33 = 0
\n" ); document.write( "Factors to
\n" ); document.write( "(x-11)(x+3) = 0
\n" ); document.write( "positive solution
\n" ); document.write( "x = 11\" is the width of the metal sheet
\n" ); document.write( "then
\n" ); document.write( "11+4 = 15\" is the length
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\n" ); document.write( "See if that's true
\n" ); document.write( "(11-6) * (15-6) * 3 =
\n" ); document.write( "5 * 9 * 3 = 135 cu/in
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