document.write( "Question 267524: Need help with the following:\r
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document.write( "A box is being constructed by cutting 3-inch squares from the corners of a rectangualr sheet of metal that is 4 inches longer than it is wide. If the box is to have a volume of 135 cubic inches, find the dimensions of the metal sheet. \n" );
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Algebra.Com's Answer #196347 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! A box is being constructed by cutting 3-inch squares from the corners of a rectangular sheet of metal that is 4 inches longer than it is wide. \n" ); document.write( " If the box is to have a volume of 135 cubic inches, find the dimensions of the metal sheet. \n" ); document.write( ": \n" ); document.write( "Assume they mean an open box. \n" ); document.write( ": \n" ); document.write( "Cutting 3\" squares from each corner make the box base dimensions 6\" less than the metal sheet \n" ); document.write( "We know the height of the box = 3\" therefore: \n" ); document.write( "Area of the base = \n" ); document.write( ": \n" ); document.write( "Let x = width of the metal \n" ); document.write( "then we can say: \n" ); document.write( "(x+4) = length of the metal \n" ); document.write( ": \n" ); document.write( "The base of the box dimensions: (x-6) by (x+4-6) \n" ); document.write( "The area \n" ); document.write( "(x-6)*(x-2) = 45 \n" ); document.write( "FOIL \n" ); document.write( "x^2 - 2x - 6x + 12 = 45 \n" ); document.write( "x^2 - 8x + 12 - 45 = 0 \n" ); document.write( "x^2 - 8x - 33 = 0 \n" ); document.write( "Factors to \n" ); document.write( "(x-11)(x+3) = 0 \n" ); document.write( "positive solution \n" ); document.write( "x = 11\" is the width of the metal sheet \n" ); document.write( "then \n" ); document.write( "11+4 = 15\" is the length \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "See if that's true \n" ); document.write( "(11-6) * (15-6) * 3 = \n" ); document.write( "5 * 9 * 3 = 135 cu/in \n" ); document.write( " |