document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=267634>Question 267634</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The ratio of an angle to its supplement is 3:7. Find the ratio of the angle to its complement.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #196341 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=196341\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The ratio of an angle to its supplement is 3:7. Find the ratio of the angle to its complement. <BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "x/(180-x) = 3/7<BR>\n" );
document.write( "Cross-multiply and solve for \"x\":<BR>\n" );
document.write( "7x = 3(180-x)<BR>\n" );
document.write( "7x = 540-3x <BR>\n" );
document.write( "10x = 540<BR>\n" );
document.write( "x = 54 degrees (the angle)<BR>\n" );
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document.write( "Complement = 90-54 = 26<BR>\n" );
document.write( "Ratio of angle to complement: 54/26 = 27/13 = 27:13<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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