document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=33172>Question 33172</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Express 1 + 2i in polar form. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #19634 by </B><A HREF=/tutors/aboutme.mpl?userid=venugopalramana><B>venugopalramana(3286)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=venugopalramana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.geocities.com/venugopalramana/FREE_MATHS_ASSISTANCE.html valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=19634\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Z=1+2i...DIVIDE AND MULTIPLY BY |Z| <BR>\n" );
document.write( "|Z|=SQRT(1^2+2^2)=SQRT(5)=R SAY.....<BR>\n" );
document.write( "Z= SQRT(5)*(1/SQRT(5)+i*(2/SQRT(5))...LET<BR>\n" );
document.write( "COS(A)=1/SQRT(5)...THEN......SIN(A)=2/SQRT(5)...SO<BR>\n" );
document.write( "Z=R{COS(A)+iSIN(A)}=R*E^(iA)WHERE R AND A ARE AS GIVEN ABOVE ...IN POLAR FORM THEY ARE................{SQRT(5),COS INVERSE(1/SQRT(5)} </SPAN>\n" );
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