document.write( "Question 267614: how many liters of 20% alcohol soltuion must be mixed with 10 liters of a 50% solution to get a 30% solution? \n" ); document.write( "
Algebra.Com's Answer #196330 by Alan3354(69443)\"\" \"About 
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how many liters of 20% alcohol soltuion must be mixed with 10 liters of a 50% solution to get a 30% solution?
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\n" ); document.write( "0.20*x + 0.50*10 = 0.30*(x + 10)
\n" ); document.write( "2x + 50 = 3x + 30
\n" ); document.write( "x = 20 liters of 20%
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