document.write( "Question 33190: 6. What is the directrix of the parabola with the equation ? \n" );
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Algebra.Com's Answer #19633 by venugopalramana(3286)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "STANDARD EQN.OF PARABOLA IS \n" ); document.write( "(X-H)^2=4A(Y-K)...WHERE \n" ); document.write( "FOCUS IS (H,K+A) \n" ); document.write( "DIRECTRIX IS Y-K+A=0 \n" ); document.write( "AXIS IS X-H=0 \n" ); document.write( "VERTEX IS (H,K) \n" ); document.write( "HERE WE HAVE \n" ); document.write( "(X+2)^2=10(Y+3)...SO COMPARING WE GET \n" ); document.write( "H=-2.....K=-3.....4A=10...OR...A=2.5...HENCE \n" ); document.write( "DIRECTRIX IS GIVEN BY \n" ); document.write( "Y-K+A=0....OR..... \n" ); document.write( "Y-(-3)+2.5=0 \n" ); document.write( "Y+3+2.5=0 \n" ); document.write( "Y+5.5=0 \n" ); document.write( "2Y+11=0 \n" ); document.write( " |