document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=267589>Question 267589</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Penny is making punch for Sam's party. The recipe requires twice as much orange juice as cranberry juice and 8 times as much ginger ale as cranberry juice. if she plans to make 176 ounces of punch, how much of each ingredient should she use? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #196323 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=196323\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x=amount of cranberry juice needed<BR>\n" );
document.write( "Then 2x=amount of orange juice needed<BR>\n" );
document.write( "And 8x=amount of ginger ale needed<BR>\n" );
document.write( "Now our equation to solve is:<BR>\n" );
document.write( "x+2x+8x=176  collect like terms<BR>\n" );
document.write( "11x=176  divide each side by 11<BR>\n" );
document.write( "x=16 oz-----------------amount of cranberry juice needed<BR>\n" );
document.write( "2x=2*16=32 oz------------amount of orange juice needed<BR>\n" );
document.write( "8x=8*16= 128 oz-------------amount of ginger ale needed\r<BR>\n" );
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document.write( "Ck<BR>\n" );
document.write( "16+32+128=176<BR>\n" );
document.write( "176=176\r<BR>\n" );
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document.write( "Hope this helps---ptaylor </SPAN>\n" );
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