document.write( "Question 267545: lois and clark leave thier office to meet clients. lois leaves at 8 am and travels at 35moh. clark leaves at 815am and travels at 40 miles an hour. they travel in opposite directions. when will they be 290 miles apart? \n" ); document.write( "
Algebra.Com's Answer #196302 by stanbon(75887)\"\" \"About 
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lois and clark leave thier office to meet clients. lois leaves at 8 am and travels at 35moh. clark leaves at 815am and travels at 40 miles an hour. they travel in opposite directions. when will they be 290 miles apart?
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\n" ); document.write( "Lois DATA:
\n" ); document.write( "rate = 35 mph ; time = x hrs. ; distance = 35x miles
\n" ); document.write( "-------
\n" ); document.write( "Clark DATA:
\n" ); document.write( "rate = 40 mph ; time = x-(1/4) hr ; distance = 40(x-(1/4)) = 40x-10 miles
\n" ); document.write( "-----------------------
\n" ); document.write( "Equation:
\n" ); document.write( "distance + distance = 290 miles
\n" ); document.write( "35x + 40x-10 = 290
\n" ); document.write( "75x = 300
\n" ); document.write( "x = 4 hrs
\n" ); document.write( "---
\n" ); document.write( "290 miles apart at 8:00 + 4 hrs = 12:00 noon
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H. \n" ); document.write( "
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