document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=267507>Question 267507</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve by completing square\r<BR>\n" );
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document.write( "(2y-3)^2=5 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #196289 by </B><A HREF=/tutors/aboutme.mpl?userid=drk><B>drk(1908)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=drk><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=196289\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> step 1 - foil out the left side to get<BR>\n" );
document.write( "(2y-3)(2y-3) = 5<BR>\n" );
document.write( "first: 2y*2y = 4y^2<BR>\n" );
document.write( "outer: 2y*(-3) = -6y<BR>\n" );
document.write( "inner: (-3*2y = -6y<BR>\n" );
document.write( "last: (-3)*(-3) = 9<BR>\n" );
document.write( "combine the -6y and -6y to get -12y. So, we get<BR>\n" );
document.write( "4y^2 - 12y + 9 = 5<BR>\n" );
document.write( "step 2 - subtract 5 to get<BR>\n" );
document.write( " 4y^2 - 12y + 4 = 0<BR>\n" );
document.write( "step 3 - divide by 4 to get<BR>\n" );
document.write( "y^2 - 3y + 1 = 0<BR>\n" );
document.write( "step 4 - take 1/2 of the middle term squared and add it o both sides to get<BR>\n" );
document.write( "y^2 - 3y + (-3/2)^2 = -1 + (-3/2)^2<BR>\n" );
document.write( "step 5 - writ the left side as a binomial squared and simplify the right side to get<BR>\n" );
document.write( "(y-3/2)^2 = (5/4)<BR>\n" );
document.write( "step 6 - take a square root to get<BR>\n" );
document.write( "(y-3/2) = +-sqrt(5)/2<BR>\n" );
document.write( "step 7 - add 3/2 to get<BR>\n" );
document.write( "y = (3 +- sqrt(5))/2 </SPAN>\n" );
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