document.write( "Question 267374: Find two consecutive integers whose product is 6 less than the square of the larger number. \n" ); document.write( "

Algebra.Com's Answer #196260 by Ruli(21) $\"\"$ $\"About$

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The product of two consecutive integers = (x)(x+1)
\n" ); document.write( "6 less than the square of the larger number = (x+1)^ - 6
\n" ); document.write( "(x)(x+1) = (x+1)^ - 6
\n" ); document.write( "x^ + 1x = (x^ + 2x + 1) - 6
\n" ); document.write( "x^ + 1x = x^ + 2x - 5
\n" ); document.write( "x^ + 1x - x^ = x^ + 2x - 5 - x^
\n" ); document.write( "1x - 2x = 2x - 5 - 2x
\n" ); document.write( "-1x = -5
\n" ); document.write( "Divide each side by -1
\n" ); document.write( "x = 5
\n" ); document.write( "check:
\n" ); document.write( "(5)(5+1) = (5+1)^-6
\n" ); document.write( "(5)(6) = (6)^-6
\n" ); document.write( "30 = 36-6
\n" ); document.write( "30 = 30 \n" ); document.write( "

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