document.write( "Question 267392: I have a total of $6000 invested in two simple interest accounts. The annual simple interest rate on one account is 9%. The annual simple interest rate on the second account is 6%. How much is invested in each account if both accounts earn the same amount of interest? \n" ); document.write( "
Algebra.Com's Answer #196253 by drk(1908)\"\" \"About 
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This is an I = PRT problem. we have the formula
\n" ); document.write( "I = PRT and another I = PRT.
\n" ); document.write( "From above, we get
\n" ); document.write( "I = x(.09)(1)
\n" ); document.write( "and
\n" ); document.write( "I = (6000-x)(.06)(1)
\n" ); document.write( "since interest is equal set them equal to get
\n" ); document.write( ".09x = 360 - .06x
\n" ); document.write( "adding .06x we get
\n" ); document.write( ".15x = 360
\n" ); document.write( "dividing, we get
\n" ); document.write( "x = 2400 at 9%
\n" ); document.write( "6000-x = 3600 at 6%.
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