document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=33244>Question 33244</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The owner of a health-food store sells dried apples for $1.20 per quarter-pound, and dried apricots for $1.80 per quarter-pound.  How many pounds of each must he mix together to get 20lb of a mixture that sells for $1.68 per quarter-pound?   </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #19625 by </B><A HREF=/tutors/aboutme.mpl?userid=Paul><B>Paul(988)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Paul><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=19625\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x be the solution:<BR>\n" );
document.write( "Equation:<BR>\n" );
document.write( "1.2x+1.8(20-x)=1.68(20)<BR>\n" );
document.write( "1.2x-1.8x+36=33.6<BR>\n" );
document.write( "-2.4=-0.6x<BR>\n" );
document.write( "x=4<BR>\n" );
document.write( "20-4=16<BR>\n" );
document.write( "Hence, for 1.2$ there is needed to be 4lb of mixture added, and for 1.8$ there is needed to be 16lb of mixture added.<BR>\n" );
document.write( "Paul. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );